Помогите с номерами д) е) ж) з)

Решите задачу:

$\frac{5}{12} + (-\frac{7}{9}) = \frac{35-84}{108} = -\frac{49}{108}$

$- \frac{11}{42} + \frac{5}{21} = \frac{11-10}{42} = \frac{1}{42}$

$-\frac{5}{7} + 1 = -\frac{5}{7} + \frac{7}{7} = -\frac{5 - 7}{7} = - \frac{2}{7}$

$2\frac{9}{40} + (-2\frac{4}{15}) = \frac{89}{40} + (-\frac{34}{15}) = \frac{267 - 272}{120} = -\frac{5}{120} = -\frac{1}{24}$