Помогите решить:(10x-3)^2=(10x+7)^2

Question

Помогите решить:(10x-3)^2=(10x+7)^2

Answer 1

(10x - 3)^2 - (10x + 7)^2 = 0 

[  a^2 - b^2 = (a - b)(a + b) ] 

(10x - 3 - (10x + 7)) (10x - 3 + 10x + 7) = 0
(10x - 3 - 10x - 7) (10x - 3  + 10x + 7) = 0 
- 10 * (20x + 4) = 0   /:(-10)
20x + 4 = 0 
20x = - 4 
x = - 4/20
x = - 1/5
x = - 0,2