25-x2/x2-6x+5 при x=-99

Question

25-x2/x2-6x+5 при x=-99

Answer 1

(25-х²)/(х² -6х+5)=((5-х)(5+х)) /((х-5)(х-1))=(-(х-5)(5+х)) / ((х-5)(х-1))= - (5+х)/(х-1)
при х= -99
- (5-99)/(-99-1)= -(-94)/( -100)= - 94/100= - 0,94