( 2 х + 3 ) ( х - 2 ) - 14 > = 0

Question

( 2 х + 3 ) ( х - 2 ) - 14 > = 0

Answer 1

2x^2 - x - 20 ≥ 0 

2x^2 - x - 20 = 0 
D = 1 + 4*40 = 161
x1 = ( 1 + √161)/4
x2 = ( 1 - √161)/4

x ∈ ( - ∞; (1-√161)/4 ] ∪ [ (1+√161)/4 ; + ∞)