Как решить (4×1200)×х=9600; х ×(5600÷8)=21000;(7300-5300)×х=72000;х×(4500+1500)=30000

Question

Как решить (4×1200)×х=9600; х ×(5600÷8)=21000;(7300-5300)×х=72000;х×(4500+1500)=30000

Answer 1

(4*1200)*х9600
4800*х=9600
Х=9600:4800
Х=2
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Х*(5600:8)=21000
Х*700=21000
Х=21000:700
Х=30
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(7300-5300)*х=72000
2000*х=72000
Х=72000÷2000
Х=36
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Х*(4500+1500)=30000
Х*6000=30000
Х=30000÷6000
Х=5