(x^3+5x^2+2x-8)/(x^2+3x+2)=2

Question

(x^3+5x^2+2x-8)/(x^2+3x+2)=2

Answer 1

(x^3+5x^2+2x-8)/(x^2+3x+2)=2
(x^3+5x^2+2x-8 -2x^2-6x-4)/(x^2+3x+2)=0

x^2+3x+2 = x^2+2x+x+2 = x(x+2)+(x+2) = (x+2)(x+1) не равен 0
х не равен -2; х не равен -1

x^3+3x^2-4x-12 = x(x^2+3)-4(x+3) = (x^2-4)(x+3)=(x+2)(x-2)(x+3) = 0
x=-3; x=2