|2+3х|<4,7; -8《х+3《8 запишите в виде двойного неравенства

|2+3х|<4,7<br>-4,7<2+3х<4,7<br>-4,7-2<2+3х-2<4,7-2<br>-6,7<3x<2,7<br> $- \frac{67}{10} :3\ \textless \ x\ \textless \ \frac{27}{10} :3$
$- \frac{67}{10} * \frac{1}{3} \ \textless \ x\ \textless \ \frac{27}{10} : \frac{1}{3}$
$- \frac{67}{30} \textless \ x\ \textless \ \frac{27}{30} :$

|2+3х|≤8
-8≤2+3х≤8
-10≤3x≤6
$- \frac{10}{3} \leq x \leq 2$
$-3\frac{1}{3} \leq x \leq 2$

|2+3х|≤х+3
$\left \{ {2+3x \leq x+3} \atop {2x+3 \geq -(x+3)}} \right.$
$\left \{ {3x-x \leq 3-2} \atop {2x+3 \geq -x-3}} \right.$
$\left \{ {2x \leq 1} \atop {2x+x \geq -3-3}} \right.$
$\left \{ {x \leq 1/2} \atop {x \geq -2}} \right.$
x∈[-2;1/2]