Помогите срочно!!!!!!
HR=ER-FK=8-4=4; KH=FE=4√3; tg∠R=KH/HR=4√3/4=√3; KR=√(KH²+HR²)=√(48+16)=√64=8; sin∠R=KH/HR=4√3/8=√3/2;⇒ ∠R=60°;