Спасите меня ((Немогу найти

A) $\frac{3x-(x-8)}{x-4}= \frac{2x-8}{x-4}= \frac{2(x-4)}{x-4} =2$

б) $\frac{y-x}{(y-3)(y+3)} - \frac{x-3}{-(y^2-9)} = \frac{y-x}{(y-3)(y+3)} + \frac{x-3}{(y-3)(y+3)} \\ \frac{y-x+x-3}{(y-3)(y+3)}= \frac{1}{y+3}$

a) $\frac{b-a}{ab} + \frac{b-a}{b^2}= \frac{b(b-a)+a(b-a)}{ab^2}= \frac{b-ab+ab-a^2}{a^2}= \frac{b^2-a^2}{ab^2}$

б) $x^2+ \frac{2x^2}{x-2}= \frac{x^2(x-2)+2x^2}{x-2}= \frac{x^3-2x^2+2x^2}{x-2}= \frac{x^3}{x-2}$