Кто шарит , решите 3 Даю 30б

Решите задачу:

$\frac{2}{x-5} - \frac{3x-6}{6-2x} = \frac{3}{(x-3)(x-1)}\; ,\; \; \; ODZ:\; \; x\ne 5,\; x\ne 3,\; x\ne 1\\\\ \frac{2}{x-5} +\frac{3x-6}{2(x-3)} - \frac{3}{(x-3)(x-1)} =0\\\\ \frac{4(x-3)(x-1)+(3x-6)(x-5)(x-1)-6(x-5)}{2(x-5)(x-3)(x-1)} =0\\\\ \frac{4(x^2-4x+3)+(3x^2-21x+30)(x-1)-6x+30}{2(x-5)(x-3)(x-1)} =0\\\\ \frac{3x^3-20x^2+29x+12}{2(x-5)(x-3)(x-1)} =0$

$3x^3-20x^2+29x+12=0\\\\x=3:\; \; 3\cdot 3^3-20\cdot 3^2+29\cdot 3+12=0\\\\x=4:\; \; 2\cdot 4^3-20\cdot 4^2+29\cdot 4+12=0\; \; \to \\\\ 3x^3-20x^2+29x+12=(x-3)(x-4)(3x+1)\\\\x=3\notin ODZ\\\\x=4\; ,\; \; x=-\frac{1}{3}\; \; -\; \; otvet$