Математика-интегралы Помогите решить!!!

Решите задачу:

$\displaystyle \int\frac{x^2+x\sqrt[3]{x}+\sqrt{x}}{x\sqrt{x}}dx = \int(x^{1/2}+x^{-1/6}+1/x)dx = \\\\ =\frac{2}{3}x^{3/2}+\frac{6}{5}x^{5/6}+\ln|x| + C\\\\ \int\left(\frac{2}{\sqrt{9-4x^2}}+\frac{1}{e^x}\right)dx = \frac{2}{3}\int\frac{1.5d(2x/3)}{\sqrt{1-(2x/3)^2}} -e^{-x} =\\\\ =\arcsin(2x/3)-e^{-x}+C$