4\ \frac{5x-x^2-4}{x^2-2x-8}=\frac{(4-x)(x-1)}{(x-4)(x+2)}=\frac{-(x-4)(x-1)}{(x-4)(x+2)}=\frac{-(x-1)}{x+2}=\frac{-(4-1)}{4+2}= -0.5" alt="lim\ x->4\ \frac{5x-x^2-4}{x^2-2x-8}=\frac{(4-x)(x-1)}{(x-4)(x+2)}=\frac{-(x-4)(x-1)}{(x-4)(x+2)}=\frac{-(x-1)}{x+2}=\frac{-(4-1)}{4+2}= -0.5" align="absmiddle" class="latex-formula">