t = \sqrt{ \frac{2h}{g} }
t_{1}= 2 c
t_{2} = 4 с
v= gt
v_{1}= 10*2=20
v _{2} = 10*4=40
" alt="h= \frac{g t^{2} }{2} => t = \sqrt{ \frac{2h}{g} }
t_{1}= 2 c
t_{2} = 4 с
v= gt
v_{1}= 10*2=20
v _{2} = 10*4=40
" align="absmiddle" class="latex-formula">
Ответ: V1=20 м\с; t1=2c ; V2= 40 м\с; t2= 4 c