Пж срочно y*(y-5)*(y+5)-(y+2)*(y²-2x+4)

Question

Пж срочно y*(y-5)*(y+5)-(y+2)*(y²-2x+4)

Answer 1

Y(y-5)(y+5)-(y+2)(y²-2x+4)=y(y²-5²)-(y³+2³)=
=y(y²-25)-(y³+8)=y³-25y-y³-8=-25y-8