Помогите: 10 cos² x + 3 cos x - 1 = 0
10 Cos² x + 3 Cos x -1 = 0 t = Cos x, |t| ≤ 1 10t² +3t -1 = 0 D = 9 +40 = 49 t = (-3 -7)/20 = -1/2 t = (-3+7)/20 = 1/5 Cos x = -1/2 x = ± 2π/3 +2πn, n ∈ Z Cos x = 1/5 x = ± arccos(1/5) +2πn, n ∈ Z