Решите уравнение 12-(4-х)^2=х(3-х)

Question

Решите уравнение
12-(4-х)^2=х(3-х)

Answer 1

(a-b)^2 = a^2 -2ab +b^2

12-(4-х)^2=х(3-х)
12 -(16 -8x +x^2) = 3x -x^2
12 -16 +8x -x^2 = 3x -x^2
-4 +8x -x^2 -3x +x^2 = 0
5x -4 = 0
5x = 4
x = 4/5

Answer 2

12-(16-8x+x^2)=3x-x^2, 12-16+8x-x^2-3x+x^2=0,-4+5x=0, 5x=4, x=4:5, x=0,8.