∠aob=90
1) aoc=3x-5
boc=x+15
aoc+boc=aob
3x-5+x+15=90
4x=80
x=20 aob=20*3-5=55 boc=20+15=35
2)aob=90=aoc+boc
aoc=x
boc=4x+30
x+4x+30=90
5x=60
x=12
aoc=12
boc=4*12+30=78
3) aoc=90=aoc+boc
aoc=2x+25
boc=3x-35
2x+25+3x-35=90
5x=100
x=20
aoc=20*2+25=65
boc=3*20-35=25
12
a) mon=180=mok+kon
mok=3x
kon=2x+20
3x+2x+20=180
5x=160
x=32
mok=3*32=96
kon=2*32+20=84
b) mon=180=mok+kon
mok=45-x
kon=125+2x
45-x+125+2x=180
x=180-125-45
x=10
mok=45-10=35
kon=125+2*10=145