Помогите решить уравнение!!!!!!!
√(x^2-1 ) = 1-x ODS: x ≤ 1 x^2-1=(x-1)^2 x^2-1=x^2-2x+1 -1=-2x+1 2x=1+1 2x=2 x=1
√(x^2 - 1 ) = 1 - x ОДЗ x ≤ 1 x^2 - 1 = (x - 1)^2 (x - 1)(x + 1) - (x - 1)^2 = 0 (x - 1)(x + 1 - (x - 1)) = 0 (x - 1)(x + 1 - x + 1) = 0 (x - 1) *2 = 0 x - 1 = 0 x = 1 Ответ 1