(x+6)^2=?(3a-1)^2=?(3y-2)(3y+2)=?(4a+3k )(4a-3k)=*?

Question

(x+6)^2=?
(3a-1)^2=?
(3y-2)(3y+2)=?
(4a+3k )(4a-3k)=*?

Answer 1

(x+6)^2=x²+12x+36
(3a-1)^2=9a²-6a+1
(3y-2)(3y+2)=9y²+6y-6y-4=9y²-4
(4a+3k)(4a-3k)=16a²-12ak-12ak-9k²=
=16a²-9k²