Помогите буду премного благодарна решить неравенство

$( \frac{1}{2} )^{ x^{2} -4x+3.5}\ \textless \ \frac{1}{ \sqrt{2} }$

$( \frac{1}{2} )^{ x^{2} -4x+3.5}\ \textless \ (\frac{1}{{2} })^{0.5}$

${ x^{2} -4x+3.5}\ \textgreater \ {0.5}$

${ x^{2} -4x+3.5}-0.5\ \textgreater \ {0$

${ x^{2} -4x+3\ \textgreater \ {0$

${ x^{2} -4x+3=0$

$D=(-4)^2-4*1*3=4$

$x_1= \frac{4+2}{2} =3$

$x_2= \frac{4-2}{2} =1$

$(x-3)(x-1)\ \textgreater \ 0$

+ - +
----------(1)----------(3)------------
//////////// /////////////

$x$ ∈ $(-$ ∞ $;1)$ ∪ $(3;+$ ∞ $)$