Вычислите f'(-1), если f(x)=1/4x^4-3x^2-5x+6 1) 2 2) 0 3) - 10 4) - 12
2) 0
f(x) = 1/4*x^4 - 3x^2 - 5x + 6 f ' (x) = 1/4*4x^3 - 3*2x - 5 = x^3 - 6x - 5 f ' (-1) = (-1)^3 + 6*1 - 5 = - 1 + 6 - 5 = 6 - 6 = 0