Решите систему уравнений (5x+4)^{2}=9y (4x+5)^{2}=9y
( 5x + 4 )^2 = 9y ( 4x + 5 )^2 = 9y -------- ( 5x + 4 )^2 = ( 4x + 5 )^2 25x^2 + 40x + 16 - 16x^2 - 40x - 25 = 0 9x^2 - 9 = 0 9( x - 1 )( x + 1 ) = 0 X - 1 = 0 X = 1 X + 1 = 0 X = - 1 Ответ 1 ; - 1