(x-y)^2-(x+y)^2=-4xy докажите тождество
(x-y)^2-(x+y)^2=-4xy (x-y)^2-(x+y)^2= =(x-y-(x+y))*(x-y+x+y)= =(x-y-x-y)*2x= =(-2y)*2x= =-4xy -4xy=-4xy
Благодарствую