Решите систему уравнений Х^2+у^2=2 Ху=1
X = 1/y = y^(-1) y^(-2) + y^2 = 2 y^4 - 2y^2 + 1 = 0 D = 4 - 4 = 0 y^2 = 2/2 = 1 y1 = -1, x1 = -1 y2 = 1, x2 = 1