32,4 -7,5*2 целых и 2/45:6 целых и 3/11

Решите задачу:

$32,4-7,5*2 \frac{2}{45}:6 \frac{3}{11}= \frac{324}{10}- \frac{75}{10}* \frac{92}{45} : \frac{69}{11}= \frac{324}{10}- \frac{75*92}{10*45}: \frac{69}{11}=$ $\frac{324}{10}- \frac{15*46}{5*9}* \frac{11}{69}= \frac{324}{10}- \frac{3*4}{9}* \frac{11}{69}= \frac{324}{10}- \frac{4}{3}* \frac{11}{69}= \frac{324}{10}- \frac{4*11}{3*69}=$ $\frac{324}{10}- \frac{44}{207}= \frac{67068}{2070}- \frac{440}{2070}= \frac{67068-440}{2070}= \frac{66628}{440}= \frac{16657}{110}$ $=151 \frac{47}{110}$