Пожалуйста, # 937, 938

Question 1

Question 2

№937.
а) $(\frac{1}{2} : \frac{3}{4}- \frac{4}{9}): \frac{3}{5} =(\frac{1}{2} * \frac{4}{3}- \frac{4}{9}): \frac{3}{5} = (\frac{1*4}{2*3} - \frac{4}{9}): \frac{3}{5} = (\frac{2}{3} - \frac{4}{9}): \frac{3}{5} = (\frac{6}{9} - \frac{4}{9})$ $* \frac{5}{3}= \frac{6-4}{9} * \frac{5}{3} = \frac{2}{9} *\frac{5}{3}= \frac{10}{27}$
б) $\frac{1}{2}: \frac{3}{8}- \frac{4}{9} : \frac{3}{5}= \frac{1}{2}* \frac{8}{3}- \frac{4}{9} * \frac{5}{3}= \frac{1*8}{2*3}- \frac{4*5}{9*3}=\frac{8}{6}- \frac{20}{27}=\frac{72}{54}- \frac{40}{54}= \frac{32}{54} =\frac{16}{27}$
в) $\frac{3}{5}: (\frac{9}{10}- \frac{3}{5}* \frac{8}{9})= \frac{3}{5}: (\frac{9}{10}- \frac{3}{5}* \frac{8}{9})= \frac{3}{5}: (\frac{9}{10}- \frac{3*8}{5*9})= \frac{3}{5}: (\frac{9}{10}- \frac{24}{45})=$ $\frac{3}{5}: (\frac{81}{90}- \frac{48}{90})= \frac{3}{5}: \frac{81-48}{90}= \frac{3}{5}: \frac{33}{90}= \frac{3}{5}* \frac{90}{33}= \frac{3*90}{5*33}= \frac{18}{11}= 1\frac{7}{11}$
г) $\frac{3}{5}: \frac{9}{10}- \frac{3}{5}* \frac{8}{9}= \frac{3}{5}* \frac{10}{9}- \frac{3*8}{5*9}= \frac{3*10}{5*9}- \frac{8}{15}= \frac{10}{15}- \frac{8}{15}= \frac{10-8}{15} = \frac{2}{15}$
№938.
а) $4*\frac{1}{5}+4* \frac{3}{7} -4* \frac{1}{35}= \frac{4}{5}+ \frac{12}{7}- \frac{4}{35}= \frac{28}{35}+ \frac{60}{35}- \frac{4}{35}= \frac{28+60-4}{35} = \frac{64}{35}$
б) $\frac{3}{8}*5+ \frac{5}{56}- \frac{1}{7}: \frac{1}{5}= \frac{15}{8}+ \frac{5}{56}- \frac{1}{7}* 5= \frac{105}{56}+ \frac{5}{56}- \frac{5}{7}= \frac{105+5}{56}- \frac{40}{56}=$ $\frac{110-40}{56}= \frac{70}{56}= \frac{35}{28}= \frac{5}{4} = 1\frac{1}{4}$
в) $\frac{3}{2}* \frac{5}{6}+ \frac{3}{2} : \frac{9}{10}- \frac{3}{2}* \frac{13}{18} = \frac{3*5}{2*6}+ \frac{3}{2} * \frac{10}{9}- \frac{3*13}{2*18} = \frac{5}{2*2}+ \frac{3*10}{2*9}- \frac{13}{2*6} =$ $\frac{5}{4}+ \frac{5}{3}- \frac{13}{12} = \frac{15}{12}+ \frac{20}{12}- \frac{13}{12}= \frac{15+20-13}{12}= \frac{22}{12} = \frac{11}{6} =1 \frac{5}{6}$
г) $\frac{4}{5}: \frac{5}{8} - \frac{4}{5} * \frac{24}{25}+ \frac{1}{25} : \frac{5}{4} = \frac{4}{5}* \frac{8}{5} - \frac{4*24}{5*25} + \frac{1}{25} * \frac{4}{5} =$ $\frac{4*8}{5*5} - \frac{96}{125} + \frac{1*4}{25*5} = \frac{32}{25} - \frac{96}{125} + \frac{4}{125} =\frac{160}{125} - \frac{96}{125} + \frac{4}{125} = \frac{160-96+4}{125}= \frac{68}{125}$ $=0,554$