Дано
m(CaO)=224 g
HCL
----------------------
m(CaCL2)-?
224 X
CaO+2HCL-->CaCL2+H2O M(CaO)=56 g/mol , M(CaCL2)=111 g/mol
56 111
224/56 = X/111
X=444 g
ответ 444г
2)
дано
m(Al)=27 g
H2SO4
----------------
m(AL2(SO4)3)-?
V(H2)-?
27 X Y
2Al+3H2SO4-->Al2(SO4)3+3H2↑
2*27 342 3*22.4
M(Al)=27 g/mol , M(Al2(SO4)3)=342 g/mol , Vm=22.4 L/mol
27/54 = X / 342
X=171 g - соли
27/54 = Y/67.2
Y=33.6 L - водорода
ответ 171 г - соли, 33.6 л - водорода