1) ( 3(x+3)(x+3) + 3(x-3)(x-3) - 10(x^2 - 9) ) / 3(x-3)(x+3) = 0
( 3(2x^2 + 18) - 10x^2 +90 ) / 3(x-3)(x+3) = 0
4x^2 - 144 = 0
3(x-3)(x+3) не равно 0 x не равно 3 , x не равно -3
(2x - 12)(2x + 12) =0
2x - 12 = 0 или 2x + 12 = 0
x = 6 x = -6
Ответ: x = 6, x = -6