㏒²₃х³ -20㏒₉х+1=0
3㏒₃²х -20*(1/2)*㏒₃х+1= 3㏒₃²х -10*㏒₃х+1=0 замена ㏒₃х=а ОДЗ х>0
3а²-10а+1=0
D=100-12=88 √D=2√22
a₁=(10+2√22)/6 ㏒₃х=(10+2√22)/6=(5+√22)/3 х₁=3^(5+√22)/3)=∛ (3^(5+√22))
a₂=(10-2√22)/6 ㏒₃х=(10-2√22)/6 = (5-√22)/3 x₂=3^(5-√22)/3)=∛ (3^(5-√22))