Помогите, пожалуйста!

35x³)(y+z)⁴=5x²(y+z)²(7x(y+z)²)

-42x²(y+z)²=6x(7x(y+z)²)

56x(y+z)³=8(y+z)(7x(y+z)²)

Значит наибольший общий делитель 7x(y+z)²
$1) \frac{35x^3(y+z)^4}{7x(y+z)^2}= \frac{5 x^{2} (y+z)^2(7x(y+z)^2)}{7x(y+z)^2}=5 x^{2} (y+z)^2$

$2) \frac{-42x^2(y+z)^2}{7x(y+z)^2}= \frac{-6 x(7x(y+z)^2)}{7x(y+z)^2}=-6x$

$3) \frac{56x(y+z)^3}{7x(y+z)^2}= \frac{8 (y+z)(7x(y+z)^2)}{7x(y+z)^2}=8(y+z)$