Нули функции
2(x + 1)^2 - 8 = 0
2(x + 1)^2 = 8
(x + 1)^2 = 4
(x + 1)^2 - 2^2 = 0
(x + 1 - 2)(x + 1 + 2) = 0
(x + 3)(x - 1) = 0
x + 3 = 0
x = - 3
x - 1 = 0
x = 1
( - 3; 0) ; ( 1; 0)
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y = 2(x + 1)^2 - 8 = 2(x^2 + 2x + 1) - 8 = 2x^2 + 4x - 6
x0 = - b/2a = - 4/4 = - 1
y0 = - 8
( - 1; - 8) - вершина