Применяем теорему Виета:
ax²+bx+c=0, a=1
x₁+x₂=-b; x₁*x₂=c
1) x²-12x-18=0 => b=-12, c=-18
x₁+x₂=-(-12)=12
x₁*x₂=-18
2) x²+2x-9=0 => b=-2, c=-9
x₁+x₂=-(-2)=2
x₁*x₂=-9
3) 3x²+7x+2=0 |:3
x²+(7/3)x+(2/3)=0 => b=-7/3, c=2/3
x₁+x₂=-(-7/3)=7/3
x₁*x₂=2/3
4) -4x²-8x+27=0 |:(-4)
x²+2x-6,75=0 => b=-2, c=-6,75
x₁+x₂=-(-2)=2
x₁*x₂=-6,75