(5a−11b)⋅(5a+11b)−25a2, если a=3 и b=0,01

Question

(5a−11b)⋅(5a+11b)−25a2,
если a=3 и b=0,01

Answer 1

(5a−11b)⋅(5a+11b)−25a² = 25а² -121в² -25а² = -121в² = -121 * 0,01² = -1,21*0,0001=

= - 0,0121

Comments

СПАСИБО!!!

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