X^3-12x+10=0 ; [-3;2/3]

Question

X^3-12x+10=0 ; [-3;2/3]

Comments

Что нужно найти?

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Min и max?

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Да

Answer 1

Y'=3x^2-12; 3x^2-12=0; x^2=4; x=+-2; y(2)= -6; y(-2)=22; y(-3) = 19

Comments

y(2/3)=62/27=2 целых 8/27

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min=-6 max=22