Дано
W(KOH)=40%
p(KOH)=1.39 g/mL
m(C(CL)3COOH)=40 g
-----------------------------------
Vppa(KOH)-?
40
CL CL
| Х |
CL-C-COOH+KOH-->CL-C-COOK+H2O
| 56 |
CL CL
201.5
M(KOH)=56 g/mol
M(C(CL3)COOK)=201.5 g/mol
X/56 = 40/201.5
X=11.12 g
m(ppaKOH)=11.12*100%/40%=27.8 g
Vppa = 27.8 / 1.39 = 20 мл
ответ 20 мл