2sin 3x cos x =√ 3 - 2 cos3xsin x

Question

2sin 3x cos x =√ 3 - 2 cos3xsin x

Answer 1

2(sin3xcosx+cos3xsinx)=√3
sin4x=√3/2
4x=(-1)^kП/3+Пk
x=(-1)^k*П/12+Пk/4