Помогите решить (х+3)^4+ 2(х+3)^2-8=0

Question

Помогите решить (х+3)^4+ 2(х+3)^2-8=0

Answer 1

( Х + 3 )^4 + 2( Х + 3 )^2 - 8 = 0
( Х + 3 )^2 = a ; a > 0
a^2 + 2a - 8 = 0
D = 4 + 32 = 36 = 6^2
a1 = ( - 2 + 6 ) : 2 = 2
a2 = ( - 2 - 6 ) : 2 = - 4
( x + 3 )^2 = 2
X^2 + 6x + 9 - 2 = 0
X^2 + 6x + 7 = 0
D = 36 - 28 = 8 = ( 2 V 2 )^2
X1 = ( - 6 + ( 2 V 2 )) : 2 = - 3 + V 2
X2 = ( - 6 - ( 2 V 2 )) : 2 = - 3 - V 2