Решите уравнение: x(x²+x-12)=5(x-3).
X(x2+x–12)=5(x–3). x1=(–1–7)/2=–4 x2=(–1+7)/2=3 x2+x–12=(x+4)(x–3) x(x+4)(x–3)–5(x–3)=0 (x–3)(x2+4x–5)=0. x–3=0 или x2+4x–5=0 x1=3 D=16+20=36 x2=(–4–6)/2=–5 x3=(–4+6)/2=1