Sin х-cosх>1............................................

Question

Sin х-cosх>1............................................

Answer 1

Решение смотрите в приложении

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Answer 2

Sinx-cosx=√2(1/√2*sinx-1/√2cosx)=√2sin(x-π/4)
Решим неравенство √2sin(x-π/4)>1.
 sin(x-π/4)>1/√2
  π/4+2πnπ/2+2πn Ответ: π/2+2πn<x<π+2πn,n∈z.