Решите пожалуйста неравенство , объясняя каждое действие Заранее огромное спасибо

Решите задачу:

$\left \{ {{3^{x}-3^{x-3}\ \textless \ 26} \atop {(0,4)^{4-x^2} \leq 1}} \right. \; \left \{ {{3^{x}-3^{x}\cdot 3^{-3}\ \textless \ 26} \atop {(0,4)^{4-x^2} \leq (0,4)^0}} \right. \; \left \{ {{3^{x}\cdot (1-3^{-3})\ \textless \ 26} \atop {4-x^2 \geq 0}} \right. \\\\ \left \{ {{3^{x}\ \textless \ 26:(1-\frac{1}{27})} \atop {x^2-4 \leq 0}} \right. \; \left \{ {{3^{x}\ \textless \ 26:\frac{26}{27}} \atop {(x-2)(x+2) \leq 0}} \right. \; \left \{ {{3^{x}\ \textless \ 27} \atop {-2 \leq x \leq 2}} \right. \; \left \{ {{3^{x}\ \textless \ 3^3} \atop {-2 \leq x \leq 2}} \right.$

$\left \{ {{x\ \textless \ 3} \atop {-2 \leq x \leq 2}} \right. \; \; \; \Rightarrow x\in [-2,2\; ]$