Помогите решить дроби: 1\6*(1\2-1\4)+7\8=?

$\frac16\times(\frac12-\frac14)+\frac78=$ 1
1) $\frac{\displaystyle1}{\displaystyle2}-\frac{\displaystyle1}{\displaystyle4}=\frac{2-1}4=\frac34$
2) $\frac{\displaystyle1}{\displaystyle6}\times\frac{\displaystyle3}{\displaystyle4}=\frac{1\times3}{6\times4}=\frac3{24}=\frac18$
3) $\frac{\displaystyle1}{\displaystyle8}+\frac{\displaystyle7}{\displaystyle8}=\frac88=1$