Помогите! 2 номер б)0,3/0,5х-3=-6/9х+3

Решите задачу:

$\cfrac{0.3}{0.5x-3}= \cfrac{-6}{9x+3} \\ \\ \\ \left \{ {{0.5x-3 \neq 0} \atop {9x+3 \neq 0}} \right. \ \ \to \ \ \left \{ {{0.5x\neq 3} \atop {9x \neq -3}} \right. \ \ \to \ \ \left \{ {{x\neq 6} \atop {x \neq -1/3}} \right. \\ \\ 0.3(9x+3)=-6(0.5x-3) \\ 2.7x+0.9=-3x+18 \\ 2.7x+3x=18-0.9 \\ 5.7x=17.1 \\ x=17.1:5.7 \\ x=3$