Помогите Решите уравнение: 5-3(x-2(x-2(x-2)))=2
5-3(х-2(х-2(х-2)))=2 5-3х+6(х-2(х-2))=2 5-3х+6х-12(х-2)=2 5-3х+6х-12х+24=2 6х-3х-12х=2-5-24 -9х=-27 х=-27/-9 х= 3
Ну попробуем 1) 5 - 3(x - 2(x - 2(x - 2))) = 2 5 - 2 = 3(x - 2(x - 2(x - 2))) x - 2(x - 2(x - 2)) = 1 x - 1 = 2(x - 2(x - 2)) = 2(x - 2x + 4) = 2(4 - x) x - 1 = 2(4 - x) = 8 - 2x x + 2x = 8 + 1 3x = 9 x = 3 Только проверь