Решить пожалуйста все , кроме 4

#1
$\left \{ {{3x - 3 - 2 - 2x \ \textless \ 1} \atop {3x - 4 \ \textgreater \ 0}} \right. \ \textless \ =\ \textgreater \ \left \{ {{x \ \textless \ 6} \atop {x \ \textgreater \ 4/3}} \right. \ \textless \ =\ \textgreater \$ x ∈ (4/3; 6)

#2
$\sqrt{6*12} + \sqrt{12*3} - \sqrt{4*6*3} = 6 \sqrt{2} + 6 - 6 \sqrt{2} = 6$

#3
$\frac{6 - (y + 3)}{(y - 3)(y + 3)} * \frac{ (y + 3)^{2}}{5} = \frac{3 - y}{5(y - 3)} = - \frac{1}{5}$

#5
$y = - \frac{x - 8}{4} + 1 \ \textgreater \ 0 =\ \textgreater \ \frac{x - 8}{4} \ \textless \ 1 \ \textless \ =\ \textgreater \ x \ \textless \ 4 + 8 = 12 \\ x \ \textless \ 12$