\frac{3x+1}{2}\\\
\frac{x-1-6x}{3}>\frac{3x+1}{2}\\\
\frac{-1-5x}{3}>\frac{3x+1}{2}\\\
2(-1-5x)>3(3x+1)\\\
-2-10x>3x+3\\\
-10x-3x>3+2\\\
-13x>5\\\
x<-\frac{5}{13}
" alt="\frac{x-1}{3}-2x>\frac{3x+1}{2}\\\
\frac{x-1-6x}{3}>\frac{3x+1}{2}\\\
\frac{-1-5x}{3}>\frac{3x+1}{2}\\\
2(-1-5x)>3(3x+1)\\\
-2-10x>3x+3\\\
-10x-3x>3+2\\\
-13x>5\\\
x<-\frac{5}{13}
" align="absmiddle" class="latex-formula">