1/6:(1/4x-1/3)-3/8=1/40

Решите задачу:

$\frac{1}{6} : ( \frac{1}{4} x - \frac{1}{3} ) - \frac{3}{8} = \frac{1}{40} \\ \\ ( \frac{1}{4} x - \frac{1}{3} ) = \frac{1}{40} - \frac{1}{6} + \frac{3}{8} \\ \\ ( \frac{1}{4} x - \frac{1}{3} ) = - \frac{1}{60} \\ \\ \frac{1}{4} x = - \frac{1}{60} + \frac{1}{3} \\ \\ \frac{1}{4} x = \frac{19}{60} \\ \\ x = \frac{19}{60} - \frac{1}{4} \\ \\ x = \frac{1}{15}$