(х^2-2х)^2-11(х^2-2х)+24=0

Question

(х^2-2х)^2-11(х^2-2х)+24=0

Answer 1

X^2-2x=t
 t^2-11t+24=0
  D=121-4*24=25
 x1=(11+5)/2=8                                                       x2=(11-5)2=3

x^2-2x=8                                                                 x^2-2x=3
x^2-2x-8=0                                                              x^2-2x-3=0
D=4+4*8=36                                                           D=4+4*3=16
x1=(2+6)/2=4        x2=(2-6)/2=-2                     x1=(2+4)/2=3        x2=(2-4)/2=-1