2^log8(5x-4)=3 срооочно,помогите

Question

2^log8(5x-4)=3 срооочно,помогите

Answer 1

2^(log8(5x-4)=3
log2(2^(log8(5x-4))=log2(3)
log8(5x-4)=log2(3)

5x-4=8^(log2(3))
5x-4=27
x=27+4
x=31/5

Answer 2

2^log₈ (5x-4)=3 . (2^log2 3 = 3)
2^log₈ (5x-4)= 2^log₂ 3
log₈ (5x-4)=log₂ 3
log₂³(5x-4)=log₂ 3
∛(5x-4)=3
5x-4=27
5x=31
x=6,2