(3+a)(a-3)-(a-4)^2-(8a-25)=0 (2a-3b)(4a^2+6ab+9b^2)+27b^3=8a^3

Question

(3+a)(a-3)-(a-4)^2-(8a-25)=0

(2a-3b)(4a^2+6ab+9b^2)+27b^3=8a^3

Answer 1

(3+a)(a-3)-(a-4)²-(8a-25)=0
a²-9-(a²-8a+16)-8a+25=0
a²-9-a²+8a-16-8a+25=0
0=0
(2a-3b)(4a²+6ab+9b²)+27b³=8a³
8a³-27b³+27b³=8a³
8a³=8a³