5 билет №2 плизик, заранее спасибо

$\frac{x}{x-10} - \frac{8}{x-6} = \frac{4x}{x^{2}-16x+60}$
x² - 16x + 60 = 0
x₁ + x₂ = 16
x₁ * x₂ = 60
x₁ = 6; x₂ = 10
x² - 16x + 60 = (x - 6)(x - 10)
$\frac{x}{x-10} - \frac{8}{x-6} = \frac{4x}{(x-6)(x-10)}$
$\frac{x}{x-10} - \frac{8}{x-6} - \frac{4x}{(x-6)(x-10)} = 0$
$\frac{x(x-6)-8(x-10)-4x}{(x-6)(x-10)} = 0$
x (x - 6) - 8 (x - 10) - 4x = 0
x² - 6x - 8x + 80 - 4x = 0
x² - 18x + 80 = 0
x₁ + x₂ = 18
x₁ * x₂ = 80
x₁ = 8; x₂ = 10

Ответ: x₁ = 8; x₂ = 10.